What Will the Balance D Read if Block a Is Pulled Up Out of the Liquid?

Block  A in the figure shown here hangs by a string from dynamometer (spring balance) D₁ and is submerged in a liquid C contained in a chalice B. The mass of the beaker is ane kg and the mass of liquid is 1.5 kg. The readings of dynamometers D₁ and D₂ are ii.5 kg and 7.5 kg respectively. What volition be the readings of D₁ and D₂ if block A is pulled up out of liquid ?

• D₁ will read five kg and D₂ will also read v kg

• D₁ will read 7.5 kg and D_two volition also read 2.five kg

• D₁ will read 2.5 kg and D₂ will likewise read 7.5 kg

• D₁ will read 10 kg and D₂ will also read 2.5 kg

diffcult

Solution

Correct option is

D_one volition read vii.five kg and D₂ will likewise read 2.five kg

When torso A is immersed in liquid , it experiences upthruts U, which makes dynamometer D₁ read :

Apparent weight =True weight – Upthrust

= W_A – U = 2.v kg-wt              (i)

Dynamometer D₂ reads ;

weight of B + weight of C + reaction = upthruts of A

or Due west_B + W_C + U = 7.5 kg-wt

As W_B = 1 kg-wt, W_C = 1.5 kg-wt

\ 1 + ane.five + U = 7.5 kg-wt

or  U = 5 kg-wt

From Wq. (1), Due west_A = U + 2.v = vii.v kg-wt

Hence, on pulling weight A out of liquid dynamometer

D_i reads its true weight seven.5 kg-wt and dynamometer

D_ii reads weight of beaker and liquid in information technology, which is ii.5 kg-wt.

Hence, the correct answer is choice (b).

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Source: https://www.kaysonsmedical.com/questions/p-span-sty_23469

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